I want to make the label that on click on it to make call to number. I know that iOS has this option, but how can I do it in Swift?
I found just how to do it in ObjC:
-(IBAction)callPhone:(id)sender {
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel:2135554321"]];
}
Can anyone help me with it?
UIApplication.sharedApplication().openURL(NSURL(string: "tel://2135554321"))
example
if let CallURL:NSURL = NSURL(string:"tel://\(yourMobileNUmber)") {
let application:UIApplication = UIApplication.sharedApplication()
if (application.canOpenURL( CallURL)) {
application.openURL( CallURL);
}
else
{
// your number not valid
let tapAlert = UIAlertController(title: "Alert!!!", message: "Your mobile number is invalid", preferredStyle: UIAlertControllerStyle.Alert)
tapAlert.addAction(UIAlertAction(title: "OK", style: .Destructive, handler: nil))
self.presentViewController(tapAlert, animated: true, completion: nil)
}
}
Type-2
// add gesture to your Label
var tapGesture = UITapGestureRecognizer(target: self, action: Selector("handleTap:"))
yourLabelName.userInteractionEnabled=true
yourLabelName.addGestureRecognizer(tapGesture)
// handle the function of UILabel
func handleTap(sender:UITapGestureRecognizer){
if let CallURL:NSURL = NSURL(string:"tel://\(yourMobileNUmber)") {
let application:UIApplication = UIApplication.sharedApplication()
if (application.canOpenURL( CallURL)) {
application.openURL( CallURL);
}
else
{
// your number not valid
let tapAlert = UIAlertController(title: "Alert!!!", message: "Your mobile number is invalid", preferredStyle: UIAlertControllerStyle.Alert)
tapAlert.addAction(UIAlertAction(title: "OK", style: .Destructive, handler: nil))
self.presentViewController(tapAlert, animated: true, completion: nil)
}
}
}