I have this in my model called B:
public function getA() {
return $this->hasOne(\app\models\A::className(), ['id' => 'A_Id']);
}
public function getDispName() {
return $this->a->attr . ' ' . $this->attr . ' ' . $this->attr2;
}
works everything fine, until I go to Create. Then I get the following "error":
PHP Notice – yii\base\ErrorException Trying to get property of non-object
As a workaround I have done this:
public function getDispName() {
if (is_object($this->a)) {
return $this->a->attr . ' ' . $this->attr . ' ' . $this->attr2;
}
}
I'm not sure if this is a good solution, or why do I get this "notice" only at create, but I would like to understand and do it correctly. I don't want this to cause problems somewhere else. Maybe I miss something other basic and important knowledge. If you have any ideas, I would be grateful to hear it. Thanks.
You are probably trying to use a B model that does not have a A model attached. If that is the case of course your function would fail. Are you sure for every B you have an A? Probably you are inserting a B and not inserting an A and trying to show info on it.
Your options are:
1) do exactly like you did, maybe change it to
public function getDispName() {
$display = '';
if (is_object($this->a)) {
$display = $this->a->attr;
}
return $display . ' ' . $this->attr . ' ' . $this->attr2;
}
2) fix your code to always make sure you insert an A when you insert a B. It can be an empty record but it has to be a record.