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stringlualua-patterns

How to filter the errormessage in a Lua string

With luasec I recieve the following answer:

blablabla..result="0"><header result="0"><office msgtype="error" msg="Administratie 355140001 bestaat niet." result="0">355140001</office><code>K..blablabla

How can I filter the text between the quotes behind "msg="?

With the function string.find (responsetable,"msg=") I can find the first character, but how can I read the rest of the string until the last quote. (the length of the errormessage is different).

Solution

  • To get the content, use string.match:

    str:match('msg="(.-)"')
--Administratie 355140001 bestaat niet.

    Note that use of - for 0 or more lazy repetitions.