In this page http://cseweb.ucsd.edu/classes/fa09/cse130/misc/prolog/goat_etc.html it is demonstrated how to solve the popular wolf, goat and cabbage puzzle.
change(e,w).
change(w,e).
move([X, X,Goat,Cabbage], wolf,[Y, Y,Goat,Cabbage]) :- change(X,Y).
move([X,Wolf, X,Cabbage], goat,[Y,Wolf, Y,Cabbage]) :- change(X,Y).
move([X,Wolf,Goat, X],cabbage,[Y,Wolf,Goat, Y]) :- change(X,Y).
move([X,Wolf,Goat,Cabbage],nothing,[Y,Wolf,Goat,Cabbage]) :- change(X,Y).
oneEq(X,X,_).
oneEq(X,_,X).
safe([Man,Wolf,Goat,Cabbage]) :-
oneEq(Man,Goat, Wolf),
oneEq(Man,Goat,Cabbage).
solution([e,e,e,e],[]).
solution(Config,[FirstMove|OtherMoves]) :-
move(Config,FirstMove,NextConfig),
safe(NextConfig),
solution(NextConfig,OtherMoves).
But in order to find an actual solution with this program it is necessary to specify the exact number of moves needed, like this:
?- length(X,7), solution([w,w,w,w],X).
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, wolf, goat, cabbage, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
X = [goat, nothing, cabbage, goat, wolf, nothing, goat] ;
false.
Is there a standard way to find a minimum moves solution without having to specify the number of moves in the above program?
length/2 has generative capability, then just avoid specifying the value:
?- length(X,_),solution([w,w,w,w],X).