I have a string: pairs = ['AA';'AB';'BB';'AC'; 'CC'; 'CB';'DE'; 'BC']
How can I delete the element which has the same characters in its string like 'AA','BB', 'CC' ?
The expected output should be: out = ['AB';'AC';'CB';'DE';'BC']
Use logical indexing and compare first and second column:
out = pairs(pairs(:,1)~=pairs(:,2),:)
For a more general way (to cover rows with more than two characters) you can create the index of rows that have all elements equal to each other using bsxfun:
allsame = any(~bsxfun(@eq, pairs, pairs(:,1)), 2);
out = pairs(allsame,:);