PHP Comparisons with multiple conditions

Question

Is it right to write this ?

 if($site!=1 || $site!=4)

I want to execute a code if the site ID isn't 1 or 4. Two negations are possible with a OR? Because it doesn't work.

Thanks!

Answer 1

When you using || if any of them satisfies it will be executed. When you dont want the both should be satisfied the you need to use &&. Should be -

if($site!=1 && $site!=4)

It will check the both conditions, i.e. $site is not equals to 1 or 4.

OR you can use in_array -

if(!in_array($site, array(1, 4)))

Currently it will check $site is 1 or not first, if it is not it will go inside the condition and ignore the rest of the conditions. So for 4 it will not be checked.