perl fork doesn't work properly when run remotely (via ssh)

Question

I have a perl script, script.pl which, when run, does a fork, the parent process outputs its pid to a file then exits while the child process outputs something to STOUT and then goes into a while loop.

$pid = fork();

if ( ! defined $pid ) 
{
    die "Failed to fork.";
}
#Parent process
elsif($pid)
{
    if(!open (PID, ">>running_PIDs"))
    {
        warn "Error opening file to append PID";
    }
    print PID "$pid  \n";
    close PID;
}
#child process
else
{
    print "Output started";

    while($loopControl)     
    {
           #Do some stuff
    }
}

This works fine when I call it locally ie: perl script.pl.

The script prints out some things then returns control back to the shell. (while the child process goes off into its loop in the background).

However, when I call this via ssh control is never returned back to the shell (nor is the "Output started" line ever printed.

ie: $ ssh [email protected] 'perl script.pl'

However, the interesting thing is, the child process does run (I can see it when I type ps).

Can anyone explain whats going on?

EDIT:

I ran it under debug and got this:

### Forked, but do not know how to create a new TTY.

Since two debuggers fight for the same TTY, input is severely entangled.

I know how to switch the output to a different window in xterms and OS/2 consoles only. For a manual switch, put the name of the created TTY in $DB::fork_TTY, or define a function DB::get_fork_TTY() returning this.

On UNIX-like systems one can get the name of a TTY for the given window by typing tty, and disconnect the shell from TTY by sleep 1000000.

Answer 1

Whenever you launch background jobs via non-interactive ssh commands, you need to close or otherwise tie off stdin, stdout, & stderr. Otherwise ssh will wait for the backgrounded process to exit. FAQ.

This is called disassociating or detaching from the controlling terminal and is a general best practice when writing background jobs, not just for SSH.

So the simplest change that doesn't mute your entire command is to add:

#close std fds inherited from parent
close STDIN;
close STDOUT;
close STDERR;

right after your print "Output started";. If your child process needs to print output periodically during its run, then you'll need to redirect to a log file instead.