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pythonluaredis

Why I keep getting this error " Wrong number of args calling Redis command From Lua script" even I get desired output


I trying to execute this lua script i get proper output too. But i keep getting Wrong number of args calling Redis command From Lua script

def new_get_following(self, start, count, user_id=0):
        script = """
        local envs = redis.call('zrevrange',KEYS[1],ARGV[3],ARGV[4]);
        redis.call('sadd',ARGV[1],unpack(envs));
        local favs = redis.call('sinter',ARGV[2],ARGV[1]);
        local acts= redis.call('mget',unpack(envs));
        redis.call('del',ARGV[1]);
        return {favs,envs,acts}
        """
        count = int(start) + int(count) - 1
        print count
        fav_key = self.fav_key + ":" + str(user_id)
        following_stream_key = self.following_stream_key + ":" + str(user_id)
        tmp_key = int(time.time())
        return self.exectute(script, args=[tmp_key, fav_key, start, count], keys=[following_stream_key])

Solution

  • Maybe it is just a typo and has already been corrected but:

    self.exectute shouldn't it be self.execute?