I have a list, containing the alphabet.
When outputting with foreach, i will currently receive this result:
What i would like to achieve is this
Ive tried the following, but really, i doesent find it a good or stable solution - and the letters/indexes are presented twice.
@{
var ie = 0;
int sortI = 0;
}
int columns = 3;
int dictLength = ToShow.Count();
int rows = dictLength/columns;
int sortS = 1;
List<int> hasKey = new List<int>();
var newDict = new Dictionary<string, List<LoopItem> >();
if( sort.Equals("alphabetically") )
{
while( sortI <= rows )
{
<text>Column @( ToShow.Keys.ElementAt(sortI) ) - </text>
while( sortS <= ( columns ) )
{
int index = (( sortS * columns ) + sortI); //(( sortS * columns ) + ( 1 + sortI ));
if( hasKey.Contains(index) ) { continue; } else
{
<text>Column @( ToShow.Keys.ElementAt(index) ) - </text>
sortS++;
hasKey.Add(index);
}
}
<text><br /></text>
sortS = 1;
sortI++;
}
sortS = 1;
sortI = 1;
<text><hr /></text>
foreach( var item in ToShow )
{
<text><br/>::Række 1::<br /></text>
while( columns >= sortS )
{
<text>Indsæt @(sortI+sortS)<br /></text>
sortS++;
}
sortI++;
sortS = 1;
}
}
}
Are there any algorithm for this kind of stuff? Or a simple function?
Thanks in advance
If you know how many letters you want to present on each row you could do something like this:
var alphabet = new []{'A', 'B', 'C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
var rows = 3;
var alphabetIndex = 0;
for(var row = 0; row < rows; row++) {
for(var letter = alphabetIndex; letter < 26; letter += rows) {
Console.Out.Write(alphabet[letter] + " ");
if(letter + rows >= 26)
alphabetIndex = (letter + rows) - 26;
}
Console.Out.WriteLine();
}
Rows will set how many rows you want, other than that it should work out for you.