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mysqlprimary-keyreferential-integrityinformation-schema

Showing MYSQL table columns with key types and reference


I need a query (INFORMATION_SCHEMA) which will for given schema and table name show me all table columns with following attributes (what key type it is: PK=>Primary Key, UQ=>Unique Key, FK=>Foreign Key, what is key name, and if it is Foreign Key what schema.table.column is referenced):

COLUMN_NAME | DATA_TYPE | KEY_TYPE | KEY_NAME    | REFERENCED
============+===========+==========+=============+========================
empid       | int       | PK       | PRIMARY     |
empname     | varchar   | UQ       | uq_empname  |
empactive   | enum      |          |             |
empcatid    | int       | FK       | fk_emp_cat  | schema.categories.catid

This is my SQL:

SELECT c.COLUMN_NAME,
       c.COLUMN_KEY,
       c.DATA_TYPE,
       k.REFERENCED_TABLE_SCHEMA,
       k.REFERENCED_TABLE_NAME,
       k.REFERENCED_COLUMN_NAME
FROM information_schema.COLUMNS c
LEFT JOIN information_schema.KEY_COLUMN_USAGE k 
    ON (k.TABLE_SCHEMA=c.TABLE_SCHEMA 
        AND k.TABLE_NAME=c.TABLE_NAME 
        AND k.COLUMN_NAME=c.COLUMN_NAME 
        AND k.POSITION_IN_UNIQUE_CONSTRAINT IS NOT NULL)
 WHERE c.TABLE_SCHEMA='PHPDAO' 
      AND c.TABLE_NAME='employees';

Here are my TABLES:

-- -----------------------------------------------------
-- Table `PHPDAO`.`categories`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `PHPDAO`.`categories` (
  `catid` INT UNSIGNED NOT NULL AUTO_INCREMENT,
  `catname` VARCHAR(50) NOT NULL,
  `catgroup` ENUM('A', 'B', 'C') NOT NULL DEFAULT 'A',
  PRIMARY KEY (`catid`))
ENGINE = InnoDB;


-- -----------------------------------------------------
-- Table `PHPDAO`.`employees`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `PHPDAO`.`employees` (
  `empid` INT UNSIGNED NOT NULL AUTO_INCREMENT,
  `empname` VARCHAR(100) NOT NULL,
  `empactive` ENUM('Y', 'N') NOT NULL DEFAULT 'Y',
  `empcatid` INT UNSIGNED NOT NULL,
  PRIMARY KEY (`empid`),
  INDEX `fk_emp_cat_idx` (`empcatid` ASC),
  UNIQUE INDEX `uq_empname` (`empname` ASC),
  UNIQUE INDEX `uq_empid` (`empid` ASC),
  CONSTRAINT `fk_emp_cat`
    FOREIGN KEY (`empcatid`)
    REFERENCES `PHPDAO`.`categories` (`catid`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

Solution

  • This is my last (pivotized) query:

    SELECT c.COLUMN_NAME,
           --c.COLUMN_KEY,
           IF(EXISTS(select *
                     FROM information_schema.KEY_COLUMN_USAGE k
                     JOIN information_schema.TABLE_CONSTRAINTS tc 
                       ON (k.TABLE_SCHEMA=tc.TABLE_SCHEMA 
                           AND k.TABLE_NAME=tc.TABLE_NAME 
                           AND k.CONSTRAINT_NAME=tc.CONSTRAINT_NAME)
                    WHERE k.TABLE_SCHEMA=c.TABLE_SCHEMA 
                          AND k.TABLE_NAME=c.TABLE_NAME 
                          AND tc.CONSTRAINT_TYPE='PRIMARY KEY' 
                          AND c.COLUMN_NAME=k.COLUMN_NAME),'PK',null) AS PK,
           IF(EXISTS(select *
                     FROM information_schema.KEY_COLUMN_USAGE k
                     JOIN information_schema.TABLE_CONSTRAINTS tc 
                       ON (k.TABLE_SCHEMA=tc.TABLE_SCHEMA 
                          AND k.TABLE_NAME=tc.TABLE_NAME 
                          AND k.CONSTRAINT_NAME=tc.CONSTRAINT_NAME)
                    WHERE k.TABLE_SCHEMA=c.TABLE_SCHEMA 
                          AND k.TABLE_NAME=c.TABLE_NAME 
                          AND tc.CONSTRAINT_TYPE='UNIQUE' 
                          AND c.COLUMN_NAME=k.COLUMN_NAME),'UQ',null) AS UQ,
           IF(EXISTS(select *
                     FROM information_schema.KEY_COLUMN_USAGE k
                     JOIN information_schema.TABLE_CONSTRAINTS tc 
                       ON (k.TABLE_SCHEMA=tc.TABLE_SCHEMA 
                          AND k.TABLE_NAME=tc.TABLE_NAME 
                          AND k.CONSTRAINT_NAME=tc.CONSTRAINT_NAME)
                    WHERE k.TABLE_SCHEMA=c.TABLE_SCHEMA 
                          AND k.TABLE_NAME=c.TABLE_NAME 
                          AND tc.CONSTRAINT_TYPE='FOREIGN KEY' 
                          AND c.COLUMN_NAME=k.COLUMN_NAME),'FK',null) AS FK,
           c.EXTRA,
           c.IS_NULLABLE,
           c.DATA_TYPE,
           c.COLUMN_TYPE,
           c.CHARACTER_MAXIMUM_LENGTH,
           c.COLUMN_COMMENT,
           k.REFERENCED_TABLE_SCHEMA,
           k.REFERENCED_TABLE_NAME,
           k.REFERENCED_COLUMN_NAME
    FROM information_schema.COLUMNS c
    LEFT JOIN information_schema.KEY_COLUMN_USAGE k
        ON (k.TABLE_SCHEMA=c.TABLE_SCHEMA
       AND k.TABLE_NAME=c.TABLE_NAME
       AND k.COLUMN_NAME=c.COLUMN_NAME
       AND k.POSITION_IN_UNIQUE_CONSTRAINT IS NOT NULL)
     WHERE c.TABLE_SCHEMA='PHPDAO'
       AND c.TABLE_NAME='employees';
    

    But I think there has to be simpler solution.