I'm trying to get the output on my second piece of code to be Dutch. The first code gives the right output, but in English. I tried to get it in Dutch but usually i ended up with 01-01-1970, 12-12-2015 or nothing. The code should give next friday this week, unless its past monday, then it's fridat next week.
My working code but in English.
<?php
$d = strtotime('today');
switch ($d) {
case strtotime('monday'):
case strtotime('friday'):
case strtotime('saturday'):
case strtotime('sunday'):
$ff = strtotime('next friday');
$ffn = date('l d M', $ff);
echo $ffn;
break;
case strtotime('tuesday'):
case strtotime('wednesday'):
case strtotime('thursday'):
$ff = strtotime('next friday' . '+ 7days');
$fft = date('l d M', $ff);
echo $fft;
break;
default:
echo "Something went wrong";
}
?>
My code which gives a Dutch output, but the wrong date (it gives today's date, not next friday/friday next week.)
By the way, this is my first question ive asked here, so I might be a bit vague or something ;)
Just output the date using strftime() and set_locale() functions. No need to change your code logic if it is correct.
<?php
$d = strtotime('today');
$format = '%A %d %b';
setlocale(LC_TIME, 'NL_nl');
setlocale(LC_ALL, 'nl_NL');
switch ($d) {
case strtotime('monday'):
case strtotime('friday'):
case strtotime('saturday'):
case strtotime('sunday'):
$ff = strtotime('next friday');
$ffn = strftime($format, $ff);
echo $ffn;
break;
case strtotime('tuesday'):
case strtotime('wednesday'):
case strtotime('thursday'):
$ff = strtotime('next friday' . '+ 7days');
$fft = strftime($format, $ff);
echo $fft;
break;
default:
echo "Something went wrong";
}
?>