uint8_t array with dynamic variable

Question

I have an uint8_t array:

uint8_t theArray[12] = { 0x00,0x01,0x00,0x00,0x00,0x06,0xFE,0x03,0x01,0xC1,0x00,0x01 };

And I need the array that has 5 of those theArrays, but first value must change by one. 0x00, 0x01, 0x02 and so on. How can I build that array without rewriting theArray multiple times?

Answer 1

Simply copy an array and change the first value.

uint8_t array[5][12] = {
                         { 0x00, 0x01,0x00,0x00,0x00,0x06,0xFE,0x03,0x01,0xC1,0x00,0x01 }
                       } ;

for (int i = 1; i < 5; i++ )
{
  array[i][0] = i;
  for (int j = 1; j < 12; j++ )
  {
    array[i][j] = array[0][j];
  }
}

Typed in Safari.