I have a list that looks like:
a = ['01', '02', '03', '04', '05', '06', '07', '08', '09', '10']
I need to cycle through this list one element at a time but when the end of the list is reached, the cycle needs to be reversed.
For example, using itertools.cycle:
from itertools import cycle
a_cycle = cycle(a)
for _ in range(30):
print a_cycle.next()
I get:
01, 02, 03, 04, 05, 06, 07, 08, 09, 10, 01, 02, 03, 04, 05, 06, 07, 08, 09, 10, 01, 02, 03, 04, 05, 06, 07, 08, 09, 10
but what I need is:
01, 02, 03, 04, 05, 06, 07, 08, 09, 10, 10, 09, 08, 07, 06, 05, 04, 03, 02, 01, 01, 02, 03, 04, 05, 06, 07, 08, 09, 10
I need to cycle through a
for a fixed number of times, say 200.
You can cycle
the chain
of your a
and reversed
a
, eg:
from itertools import cycle, islice, chain
a = range(1, 11)
b = reversed(a)
c = cycle(chain(a, b))
d = list(islice(c, 100)) # `c` is infinite - hence the `islice` to stop at some point...
Which gives you:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1]
Note: If a
is an exhaustable iterator, you will need to make a copy of a
first. But given your example, this will be fine.