I have a set of points and would like to know if there is a function (for the sake of convenience and probably speed) that can calculate the area enclosed by a set of points.
for example:
x = np.arange(0,1,0.001)
y = np.sqrt(1-x**2)
points = zip(x,y)
given points the area should be approximately equal to (pi-2)/4. Maybe there is something from scipy, matplotlib, numpy, shapely, etc. to do this? I won't be encountering any negative values for either the x or y coordinates... and they will be polygons without any defined function.
EDIT:
points will most likely not be in any specified order (clockwise or counterclockwise) and may be quite complex as they are a set of utm coordinates from a shapefile under a set of boundaries
Implementation of Shoelace formula could be done in Numpy. Assuming these vertices:
import numpy as np
x = np.arange(0,1,0.001)
y = np.sqrt(1-x**2)
We can redefine the function in numpy to find the area:
def PolyArea(x,y):
return 0.5*np.abs(np.dot(x,np.roll(y,1))-np.dot(y,np.roll(x,1)))
And getting results:
print PolyArea(x,y)
# 0.26353377782163534
Avoiding for loop makes this function ~50X faster than PolygonArea:
%timeit PolyArea(x,y)
# 10000 loops, best of 3: 42 µs per loop
%timeit PolygonArea(zip(x,y))
# 100 loops, best of 3: 2.09 ms per loop.
Timing is done in Jupyter notebook.