This is creating a square with the width and height already set up and printing it out into the output using dashes, And it runs perfectly; But I don't seem to full understand what the second and third loop are doing and hows its running.
- (void)draw {
for (int w = 1; w <= width; w++) {
printf("-");
}
***
for (int h = 0; h <= height; h++) {
printf("\n");
printf("|");
for (int space = 0; space <= width; space++) {
printf(" ");
}
printf("|");
}
***
for (int w = 1; w <= width; w++) {
if (w == 1) {
printf("\n");
}
printf("-");
if (w == width)
printf("\n");
}
}
}
The middle loop you are asking about basically draws the left and right side of the box, one '|' at a time, from top-to-bottom... It prints the first | on the left side, then a bunch of spaces, then the first | on the right side. It then moves down to the next line and repeats all over again.
It's probably easier to visualize it:
After the first loop you're left with something like this (assuming width = 15)
---------------
Once the second starts, it inserts a newline and prints a pipe | on the left, leaving you with:
---------------
|
Then the inner loop inserts spaces for the amount your width is, (represented here as o) leaving you with this:
---------------
|ooooooooooooooo
After the spaces have been inserted, another pipe is drawn on the right side, and you're left with:
---------------
| |
This continues height times until you're left with (assuming height = 5):
---------------
| |
| |
| |
| |
| |
Finally, the last loop prints the bottom, just like the top:
---------------
| |
| |
| |
| |
| |
---------------