printf not printing unsigned int

I'm experiencing the following problem printing unsigned numbers . Here's whats happening: When I input a negative value in the array and then try to print it, I can't print the number but other amount is printed.

int cant;
int a[30][30];    

int printequation (){
    int x,y;
    for (x=0;x<cant;x++){
        for (y=0;y<cant+1;y++){
            if(y==cant){
                printf(" = %d",a[x][y]);
            }else{
                if (y==0)
                    printf(" %dX%d",a[x][y],(y+1));
                else{
                    if(a[x][y]>0){
                        printf(" + ");
                    }else{
                        printf(" - ");
                    }
                    printf("%uX%d",a[x][y],(y+1)); /*<-----------------here*/
                }
            }
        }
        printf("\n");
    }
    return 0;
}

Here's an example:

input: -2 -2 -2 
output: -2x1 -4294967294x2 = -2  /*here It should print -2 but can't get it*/

Solution

Avoid mixing mis-matched printf() format specifiers with argument types. @ouah

//v
int a[30][30];    
...
printf("%uX%d",a[x][y],(y+1));
//       ^

To print a signed int without its "sign" and work with the entire range of INT_MIN ... INT_MAX, a number of approaches:

Give up on INT_MIN and use abs() @Keith Thompson

printf("%d", abs(x));  // fails for 2's complement INT_MIN

Convert to wider integer. Fails when wider integer not available - rare.
```
printf("%lld", llabs((long long) x));
```
Convert to corresponding unsigned. Maybe trouble on rare machines whose unsigned positive range is the same as int positive range.
```
unsigned u = (unsigned) i;
if (i < 0) u = UINT_MAX - u;
printf("%u", u);
```

Print digits seprately

int msdigits = i/10;
int lsdigit = i%10;
if (msdigits) {
  printf("%d", abs(msdigits));
}
printf("%d", abs(lsdigit));