Suppose I have known java BigIntegers c, e, and n, is there a way to quickly calculate the BigInteger m, where:
c = m^e (mod n)
Well, sort of... Suppose that you have determined the number "d" such that
d*e=1 (mod phi(n))
Where phi(n) is the size of the set of relatively prime numbers relative to n. For example, if n=pq where p and q are prime, then phi(n)=(p-1)*(q-1).
Then
m=c^d (mod n)
In the case where you don't already know "d", then I think it is going to be pretty difficult for you to invert that function in general. Good luck.