not able to proceed further after providing move number in Python code for tic tac toe. It asks for next move then cell number is provided but makeMove() method is not getting executed. It will ask again next move till dont press enter key twice. Please help me to resolve this code.
#Tic Tac Toe
import random
def drawBoard(board):
# This function prints out the board that it was passed.
# "board" is a list of 10 strings representing the board (ignore index 0)
print(' | |')
print(' ' + board[7] + ' | ' + board[8] + ' | ' + board[9])
print(' | |')
print('-----------')
print(' | |')
print(' ' + board[4] + ' | ' + board[5] + ' | ' + board[6])
print(' | |')
print('-----------')
print(' | |')
print(' ' + board[1] + ' | ' + board[2] + ' | ' + board[3])
print(' | |')
def inputPlayerLetter():
# Lets the player type which letter they want to be.
#
letter = ''
while not (letter == 'X' or letter == 'O'):
#print('Do you want to be X or O?')
#letter = input().upper()
letter = (raw_input("Do you want to be X or O? ")).upper()
print "Received input is : ", letter.upper()
#
if letter == 'X':
return ['X', 'O']
else:
return ['O', 'X']
def whoGoesFirst():
# Randomly choose the player who goes first.
if random.randint(0, 1) == 0:
return 'computer'
else:
return 'player'
def playAgain():
print('Do you want to play again? (yes or no)')
return raw_input().lower().startswith('y')
def makeMove(board, letter, move):
board[move] = letter
def isWinner(bo, le):
#
#
return ((bo[7] == le and bo[8] == le and bo[9] == le) or # across the top
(bo[4] == le and bo[5] == le and bo[6] == le) or # across the middle
(bo[1] == le and bo[2] == le and bo[3] == le) or # across the bottom
(bo[7] == le and bo[4] == le and bo[1] == le) or # down the left side
(bo[8] == le and bo[5] == le and bo[2] == le) or # down the middle
(bo[9] == le and bo[6] == le and bo[3] == le) or # down the right side
(bo[7] == le and bo[5] == le and bo[3] == le) or # diagonal
(bo[9] == le and bo[5] == le and bo[1] == le)) # diagonal
def getBoardCopy(board):
# Make a duplicate of the board list and return it the duplicate.
dupeBoard = []
for i in board:
dupeBoard.append(i)
return dupeBoard
def isSpaceFree(board, move):
# Return true if the passed move is free on the passed board.
return board[move] == ' '
def getPlayerMove(board):
# Let the player type in their move.
move = ' '
while move not in '1 2 3 4 5 6 7 8 9'.split() or not isSpaceFree(board, int(move)):
print('What is your next move? (1-9)')
move = raw_input()
return int(move)
def chooseRandomMoveFromList(board, movesList):
# Returns a valid move from the passed list on the passed board.
# Returns None if there is no valid move.
possibleMoves = []
for i in movesList:
if isSpaceFree(board, i):
possibleMoves.append(i)
if len(possibleMoves) != 0:
return random.choice(possibleMoves)
else:
return None
def getComputerMove(board, computerLetter):
# Given a board and the computer's letter, determine where to move and return that move.
if computerLetter == 'X':
playerLetter = 'O'
else:
playerLetter = 'X'
# Here is our algorithm for our Tic Tac Toe AI:
# First, check if we can win in the next move
for i in range(1, 10):
copy = getBoardCopy(board)
if isSpaceFree(copy, i):
makeMove(copy, computerLetter, i)
if isWinner(copy, computerLetter):
return i
# Check if the player could win on their next move, and block them.
for i in range(1, 10):
copy = getBoardCopy(board)
if isSpaceFree(copy, i):
makeMove(copy, playerLetter, i)
if isWinner(copy, playerLetter):
return i
# Try to take one of the corners, if they are free.
move = chooseRandomMoveFromList(board, [1, 3, 7, 9])
if move != None:
return move
# Try to take the center, if it is free.
if isSpaceFree(board, 5):
return 5
# Move on one of the sides.
return chooseRandomMoveFromList(board, [2, 4, 6, 8])
def isBoardFull(board):
# Return True if every space on the board has been taken. Otherwise return False.
for i in range(1, 10):
if isSpaceFree(board, i):
return False
return True
print('Welcome to Tic Tac Toe!')
while True:
# Reset the board
theBoard = [' '] * 10
playerLetter, computerLetter = inputPlayerLetter()
turn = whoGoesFirst()
print('The ' + turn + ' will go first.')
gameIsPlaying = True
while gameIsPlaying:
if turn == 'player':
#
drawBoard(theBoard)
move = getPlayerMove(theBoard)
if isWinner(theBoard, playerLetter):
drawBoard(theBoard)
print('Hooray! You have won the game!')
gameIsPlaying = False
else:
if isBoardFull(theBoard):
drawBoard(theBoard)
print('The game is a tie!')
break
else:
turn = 'computer'
else:
#
move = getComputerMove(theBoard, computerLetter)
makeMove(theBoard, computerLetter, move)
if isWinner(theBoard, computerLetter):
drawBoard(theBoard)
print('The computer has beaten you! You lose.')
gameIsPlaying = False
else:
if isBoardFull(theBoard):
drawBoard(theBoard)
print('The game is a tie!')
break
else:
turn = 'player'
if not playAgain():
breakOutput :
Welcome to Tic Tac Toe! Do you want to be X or O? x Received input is : X The computer will go first. | | O | |
| | | |
| | | | | |
What is your next move? (1-9) 5
| | O | |
| | | |
| | O | | | | What is your next move? (1-9) 5 | | O | |
| | O | |
| | O | | | | The computer has beaten you! You lose. Do you want to play again? (yes or no)
Replace input() call with raw_input() in getPlayerMove function.
Your code doesn't work, because input() is an equivalent to eval(raw_input()). If user puts a number then input returns an integer value. That means move not in '1 2 3 4 5 6 7 8 9'.split() is always False