I am having trouble with the following scenario using python schedule module. Essentially I want to run a login event at time A, and then run the action at time B.
The code does not run as the intended behaviour describes and this is where I need help.
import sched
import datetime
today = datetime.datetime.today()
log = today.replace(hour=11, minute=59, second = 0)
action= today.replace(hour=12, minute=0, second = 0)
scheduler = sched.scheduler(datetime.datetime.today(), time.sleep)
def login_event(name):
print 'EVENT:', datetime.datetime.today(), name
def action_event(name):
print 'EVENT:' datetime.datetime.today(),name
print 'START:', time.time()
scheduler.enter(log, login_event, ('Login'))
scheduler.enter(action, login_event, ('Action'))
scheduler.run()
EDIT I have altered the code to the following but it still doesn't seem right in terms of how best to implement this behaviour.
import sched
import datetime
from datetime import timedelta
import datetime
import time
today = datetime.datetime.today()
log = datetime.datetime.now() + timedelta(minutes=1)# today.replace(hour=12, minute=46, second = 0)
action= log + timedelta(minutes=2)
scheduler = sched.scheduler(time.time, time.sleep)
print datetime.datetime.now
def login_event(name):
print 'Login:', datetime.datetime.now(), name
def action_event(name):
print 'Action:', datetime.datetime.now(), name
print 'Start:', datetime.datetime.now()
scheduler.enter(1, 1, login_event, ('first',))
scheduler.enter(60, 1, action_event, ('second',))
scheduler.run()
https://github.com/dbader/schedule
By following the pattern linked above I was able to create the desired behaviour using a slightly different schedule module
import schedule
import time
def job():
print("I'm working on job one...")
def job2():
print("I'm working on job two..")
schedule.every().day.at("10:30").do(job)
schedule.every().day.at("10:35").do(job2)
while True:
schedule.run_pending()
time.sleep(1)