Using the example table below, I would like to show:
My main question: how can I best create a list of all the edges consisting of all connected genres?
Let's say I have a table with movies and genres:
GENRE | MOVIE
--------------------------
Drama | A
Action | A
Comedy | A
Documentary | B
Romantic | B
Action | B
Drama | B
Drama | C
Romantic | C
Action | C
---------------------------
I do not have a preference for visualization framework, but the following comes close to what I had in mind: http://visjs.org/examples/network/09_sizing.html
Other suggestions to visualize are more than welcome!
Based on my movie example, the nodes and edges could look like: http://jsfiddle.net/wivaku/90oef0pg/
In this example the edges are hardcoded. In real life I would like to create them dynamically. How can I best create the edges JSON, preferably using PHP?
The PHP snippet I have at the moment:
<?php
//the SQL rows (normally from SQL, now static):
$rows = json_decode('[["Drama","A"],["Action","A"],["Comedy","A"],["Documentary","B"],["Romantic","B"],["Action","B"],["Drama","B"],["Drama","C"],["Romantic","C"],["Action","C"]]');
$nodes = array();
$edges = array();
// create nodes
$genres = array_count_values(array_map(function($i) {return $i[0]; }, $rows));
foreach ($genres as $key => $value) {
$nodes[] = array("id"=>$key, "value"=>$value);
}
// create edges
// helpful to have genres grouped by movie? (normally from SQL, now static)
$movieGenres = json_decode('[{"movie":"A","genres":["Drama","Action","Comedy"]},{"movie":"B","genres":["Documentary","Romantic","Action","Drama"]},{"movie":"C","genres":["Drama","Romantic","Action"]}]');
// ...
print json_encode(["nodes"=>$nodes, "edges"=>$edges], JSON_NUMERIC_CHECK);
?>
Thanks in advance!
Update: regarding the comments about SQL details / options. The table I have is pretty much as listed. So: genreId and contentId. One option I was exploring (as shortcut for the PHP code): concatenate the genres per movie.
SELECT GROUP_CONCAT(genreId SEPARATOR "|") AS genres
FROM contentGenres
GROUP BY contentId
ORDER BY count(genreId) DESC
With the example data:
Drama|Action|Comedy
Documentary|Romantic|Action|Drama
Drama|Romantic|Action
Or using the genre ID's:
1|2|3
4|5|2|1
1|5|2
The result of my real data set is ±11000 rows, with some movies having 8 genres.
You can do the processing at the SQL level, for instance using this query:
SELECT a.genreId,b.genreId,count(*)
FROM genres as a, genres as b
WHERE a.contentId = b.contentId AND a.genreId < b.genreId
GROUP BY a.genreId, b.genreId
The id's are numbered as the genres in your example:
1 Drama
2 Action
3 Comedy
4 Documentary
5 Romantic