Python selection limiter

Question

I am working on a project where I must ask the user to make a selection, I must limit their answers between 1-4 and have the program inform them when they have made a unacceptable selection. My issue comes when I try to modify the limiter to not crash when the user enters a empty space as a input.

No matter how I alter this code below, I receive a invalid syntax error. Any suggestions on how to fix this error? I do not know if it has anything to do with the boolean not, but that is the part of the code I added which causes the error. The original limiter was given to the entire class by the instructor.

def questionHairstyle():
    while True:
        hairchoice = ()
        questionsH = ("        1, for bald;" "\n" "        2, for crew-cut;"
        "\n" "        3, for curly;" "\n"   "        4, for wearing a hat;")
        print("Please enter a hairstyle:")
        print(questionsH)
        hairchoice = input("--> ", )
        print()
        if hairchoice[0] >= "1" and hairchoice[0] <= "4" 
        and not hairchoice[0] == " " and len(hairchoice) ==1:
        break
        print("Choice must be, between 1-4, not ", hairchoice + ".")
        print("Try again.")

The exact error message.

File "C:\Python34\Projects\sketch\sketch4.py", line 34
    if hairchoice[0] >= "1" and hairchoice[0] <= "4"
                                                    ^
SyntaxError: invalid syntax

Answer 1

I Have improvised code from @FunkySayu.

def questionHairstyle():
    while True:
        questionsH = ["    1, for bald;",
                "    2, for crew-cut;",
                "    3, for curly;",
                "    4, for wearing a hat"
                ]
        print("Please enter a hairstyle:")
        print("\n".join(questionsH))
        hairchoice = raw_input("-->")  #This will take even spaces
        print()
        if hairchoice in ["1", "2", "3", "4"]:
            break
        elif hairchoice == " ":     #This part checks for space as input from user
            print ("Space is encountered ")
            print("Choice must be, between 1-4, not ", hairchoice, ".")
            # This part of code can be extended for other user input also
        print("Try again.")


questionHairstyle()

output:

Please enter a hairstyle:
    1, for bald;
    2, for crew-cut;
    3, for curly;
    4, for wearing a hat
--> 
()
Space is encountered 
('Choice must be, between 1-4, not ', ' ', '.') #You can see the ' ' space is identified well in the output.
Try again.
Please enter a hairstyle:
    1, for bald;
    2, for crew-cut;
    3, for curly;
    4, for wearing a hat
-->