Using arg[v] as int? - Objective C

Question

I'm trying to pass arguments into and integer variable at the start of my program in xcode using Objective C. So far most methods I've found have just given me a variety of error messages or crashed my VM.

int numcols, numrows;

int main(int argc, const char * argv[]) {
@autoreleasepool {

    if (argc != 3){
        NSLog(@"%2s", "Wrong number of arguments");
        exit(1);
    }

    //numrows = (int)(argv[1] - '0'); 
    //numcols = (int)(argv[2] - '0'); These lines cause a crash
    numrows = 3;
    numcols = 4;

I want numrows to take the first argument and numcols to take the second. I went into the settings in xcode to change the starting arguments to 3 and 4, but if I check them or print them they come out as random numbers.

Answer 1

First of all your question is not clear, how much i understand i can say. As argc means argument count and argv means argument value. If you want to cast char to int. try this

[[NSString stringWithFormat:@"%s", argv[2]] intValue];