Automatic in python

Question

I've been working on an automator in python, but I'm having some trouble creating a schematic.

If the input data is (where EV is even and OD is odd):

 EV|0|EV|1|OD
 OD|0|OD|1|EV

I'm trying to create a dictionary based schematic, such that for both even and odd, there are nested dictionaries

Though I'm having a lot of trouble coming up with ideas

Answer 1

How about this:

data = 'EV|0|EV|1|OD;OD|0|OD|1|EV'

# output: {even: {0:even, 1:odd}, odd: {0:odd, 1:even}}

information = data.split(';')
output = {}
for piece in information:  # Each piece is like EV|0|EV|1|OD
    parts = piece.split('|')
    head = parts[0]  # Our dictionary key, eg. [EV]
    tail = parts[1:]  # Stuff that makes up the inner dict, e.g. [0, EV, 1, OD]

    # Use step = 2 to get key:value pairs from tail:
    inner = {tail[i]: tail[i+1] for i in range(0, len(tail)-1, 2)}

    if head not in output:
        output[head] = inner
    else:
        # What do we do here?
        pass

print(output)

Yields: {'EV': {'1': 'OD', '0': 'EV'}, 'OD': {'1': 'EV', '0': 'OD'}}

If you wanted, at the very beginning, you could do:

data = data.replace('EV', 'even').replace('OD', 'odd')