I have made this code, and it works good, but I need how to create an link(href) on the output file. I tried several ways but i just cant, don't need an answer but some pointers where to learn.
if ($row = mysqli_fetch_array($result)) {
$output = $row["id"];
}
if ($output) {
echo $output;
}
else {
echo "That is not a valid record on our database";
}
You should just echo the anchor tag with your $output
$output = $row["title"];
$output ='FirstSong'; #To test i am using this as FirstSong
echo "<a href='songs?id=".$output."'>Click here</a>"; #You can have any text for href
So your code will be
if ($row = mysqli_fetch_array($result)) {
$output = $row["title"];
}
if ($output) {
echo "<a href='songs?id=".$output."'>Click here</a>";
}
else { echo "That is not a valid record on our database"; }
Here is the demo