Show OUTSIDE div on a:hover

Question

I got this menu I've been working on, I want to make an outside div appear when I mouseover the a.

I've searched through all stackoverlow but all those solutions can't seem to work for me. I must be doing something wrong. I would appreciate some help with this.

my html

        <div id="hover1"></div>
        <div style="float: left; position: relative; left: 50%; margin-top: 237px;">
            <img src="img/octo_logo.png" class="logo" />
        </div>
        <!-- MENU start -->
        <div id="menu">
            <ul>
                <li><a href="bio.html"><span>BIO</span></a></li>
                <li><a href="equipa.html"><span>EQUIPA</span></a></li>
                <li><a href="reconhecimento.html"><span>RECONHECIMENTO</span></a></li>
                <li><a href="parceiros.html"><span>PARCEIROS</span></a></li>
                <li><a href="porque_nao.html"><span>PORQUE NÃO?</span></a></li>
                <li><a href="contactos.html"><span>CONTACTOS</span></a></li>
            </ul>
        </div>

my css:

#hover1{
    width: 155px;
    height: 650px;
    background-color: #57C194;
    float:left;
    position: absolute;
    display: none;
    }
#menu a:hover + #hover1{
    display: block;
    }

Here's a view of the menu https://i.sstatic.net/n5e9s.png

And the result I want https://i.sstatic.net/6snWn.png

EDIT: I'm willing to use jquery.

Answer 1

With what you've got above; a simple jQuery example would be something like:

$('#menu a')
.on('mouseover', function (event) {
    $('#hover1').show();
})
.on('mouseout', function (event) {
    $('#hover1').hide();
});

EDIT:

The reason might be because the DOM elements aren't ready.

Try wrapping the above code with:

$(function () {
    // above code here
});

or if that doesn't work:

$(document).ready(function () {
    // above code here
});