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bashshellgawk

Choosing lines with GAWK

I have a file with data:

 /homes/XXXX/YYYYY/file1:20150324
 /homes/XXXX/YYYYY/file2:20150327
 /homes/XXXX/YYYYY/file3:20150320
 /homes/XXXX/YYYYY/file3:20150327
 /homes/XXXX/YYYYY/file4:20150328

First field is path, : as a separator and second field is a date. What I want to do is to select only those lines with date lower then some value.

gawk -v var="$SOMEVALUE" '{FS = ":"; if($2<=var) print;}'

This is what I have. It works fine, prints lines with lower value than I want to, but it everytime prints also the first line, no matter the value. Could you give me some advice what to do? thanks

Solution

  • What about:

    gawk -F: -v var="$SOMEVALUE" 'var>=$2'

    The error is that you had to change the field separator after you read the first row.