how to test if there is any word matched the string in Python

Question

I want to write a python program to test if there are any phrase can match the string using python.

string ='I love my travel all over the world'
list =['I love','my travel','all over the world']

So I want to text if there are any one of list can match that string that can print 'I love' or 'my travel','all over the world'.

any(x in string for x in list)

Or I need to use text mining to solve the problem?

Answer 1

You can't do this:

if any(x in string for x in word_list)
    print x

Because the any function iterates through the entire string/list, discards the x variable, and then simply returns a Boolean (True or False).

You can however, just break apart your any function so that you can get your desired output.

string ='I love traveling all over the world'
word_list =['I love','traveling','all over the world']

for x in word_list:
    if x in string:
        print x

This will output:

>>>
I love
traveling
all over the world
>>>

Update using string.split() :

string =['I', 'love','traveling','all', 'over', 'the', 'world']
word_list =['I love','traveling','all over the world']
count=0
for x in word_list:
    for y in x.split():
        if y in string:
            count+=1
            if count==len(x.split()) and (' ' in x) == True:
                print x
    count=0

This will output:

>>> 
I love
all over the world
>>>