This is what my models.py looks like:
class Project(models.Model):
name = models.CharField(max_length="40", unique=True)
class Entry(models.Model):
project = models.ForeignKey(Project)
name = models.CharField(max_length="40",unique=False)
When I want to create a new entry I would use ajax to post the name of the entry to the server
And it's the createEntry which takes care of the ajax post request
def createEntry(request):
if request.method == 'POST':
response_data = {}
name = request.POST.get('name')
projectId = request.session['projectId']
try:
project = Project.objects.get(pk=projectId)
entry=Entry(name=name)
project.entry_set.add(entry)
except:
print traceback.format_exc()
return HttpResponseBadRequest("Failed")
response_data['result'] = 'Create post successful!'
return JsonResponse(response_data)
Everything goes smoothly right except that when a new entry with a same name of a existing one is being created an exception happens
Here is the traceback info
Traceback (most recent call last):
File "/home/vagrant/src/src/views.py", line 70, in createEntry
project.entry_set.add(entry)
File "/usr/local/lib/python2.7/dist-packages/django/db/models/fields/related.py", line 708, in add
obj.save()
File "/usr/local/lib/python2.7/dist-packages/django/db/models/base.py", line 589, in save
force_update=force_update, update_fields=update_fields)
File "/usr/local/lib/python2.7/dist-packages/django/db/models/base.py", line 617, in save_base
updated = self._save_table(raw, cls, force_insert, force_update, using, update_fields)
File "/usr/local/lib/python2.7/dist-packages/django/db/models/base.py", line 698, in _save_table
result = self._do_insert(cls._base_manager, using, fields, update_pk, raw)
File "/usr/local/lib/python2.7/dist-packages/django/db/models/base.py", line 731, in _do_insert
using=using, raw=raw)
File "/usr/local/lib/python2.7/dist-packages/django/db/models/manager.py", line 92, in manager_method
return getattr(self.get_queryset(), name)(*args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/django/db/models/query.py", line 921, in _insert
return query.get_compiler(using=using).execute_sql(return_id)
File "/usr/local/lib/python2.7/dist-packages/django/db/models/sql/compiler.py", line 920, in execute_sql
cursor.execute(sql, params)
File "/usr/local/lib/python2.7/dist-packages/django/db/backends/utils.py", line 81, in execute
return super(CursorDebugWrapper, self).execute(sql, params)
File "/usr/local/lib/python2.7/dist-packages/django/db/backends/utils.py", line 65, in execute
return self.cursor.execute(sql, params)
File "/usr/local/lib/python2.7/dist-packages/django/db/utils.py", line 94, in __exit__
six.reraise(dj_exc_type, dj_exc_value, traceback)
File "/usr/local/lib/python2.7/dist-packages/django/db/backends/utils.py", line 65, in execute
return self.cursor.execute(sql, params)
File "/usr/local/lib/python2.7/dist-packages/django/db/backends/sqlite3/base.py", line 485, in execute
return Database.Cursor.execute(self, query, params)
IntegrityError: UNIQUE constraint failed: src_entry.name
Here goes my question:
Since I have explicitly define the name field of the Entry with unique=False, there shouldn't be unique constraint on the name field, then how could this exception happen?
This UNIQUE constraint is being enforced by the database. You will need to run a migration to remove the constraint.