I wrote code in mips 32 to get 10 numbers from the user less than 25, have an array with 25 elements and store a 7 in each index the user enters. For example if the user enters 3 4 5..there will be a 7 stored in the 3rd, 4th and 5th positions of the array. This is what I have:
.data
prompt: .asciiz "Please input 10 integers between 0 and 25:\n"
i: .byte 0
k: .byte 0
ARRAY1: .space 25
newline: .asciiz "\n"
.text
_start:
main: la $a0, prompt
li $v0, 4
syscall
la $t0, ARRAY1
lb $t1, i
li $t2, 10
li $t4, 25
lb $t5, k
li $t9, 7
get_input_loop: li $v0, 5
syscall
add $t0, $t0, $v0
sb $t9, ($t0)
sub $t0, $t0, $v0
addi $t1, $t1, 1
blt $t1, $t2, get_input_loop
la $t0, ARRAY1
print: add $t0, $t0, $t5
lb $t6, ($t0)
move $a0, $t6
li $v0, 1
syscall
addi $t5, $t5, 1
blt $t5, $t4, print
li $v0, 10
syscall
For some reason the 7s don't get stored in the indices the user provides. Could someone tell me what I'm doing wrong?
You should have used a debugger/simulator to step through your code. Then you would have seen the 7s are stored into the right place, you are just printing the array wrong. You are adding 1 to $t5 and adding $t5 to $t0 in every iteration, so what you are printing are the indices 0, 1, 3, 6, 10, .... Your print loop should look more like:
print: lb $t6, ($t0)
move $a0, $t6
li $v0, 1
syscall
addi $t0, $t0, 1
addi $t5, $t5, 1
blt $t5, $t4, print