How to hide "react-bootstrap modal" form that has preventDefault() inside its onSubmit?

Question

The problem is that when I do not use preventDefault(), page is reloaded onSubmit and hidden. When preventDefault is used my form is doing what it has in onSubmit, but it is not hiding after submit. When I use other "Close" button that has only

onClick={this.props.onRequestHide}   

form is hiding just fine.

How to hide that form when it is done with its onSubmit.

  <Modal {...this.props} className="adressModal" bsStyle="primary" title='Adress Form' animation={false}>
    <form className="addressModal" onSubmit={this.handleSubmit} >
      <div className="modal-body">
        <Input type="text" placeholder="Enter Kraj" className="form-control" valueLink={this.linkState('address')} ref="address" hasFeedback required/>
      </div>
      <div className="modal-footer">
      <ButtonGroup>
        <Button className="btn btn-default" onClick={this.props.onRequestHide} data-dismiss="modal" active>Close</Button>
        <Button bsStyle="primary" className="btn btn-default" type="submit" disabled={this.state.isSubmitting} >Save</Button>
  </ButtonGroup>
  </div>
    </form>
</Modal>

Code is just mix of ModalTrigger example from http://react-bootstrap.github.io/components.html#modals and React basic tutorial
http://facebook.github.io/react/docs/tutorial.html.

Answer 1

You could just call the this.props.onRequestHide function inside of the handleSubmit function

something like this:

handleSubmit: function() {
  /* ... */
  this.props.onRequestHide();
  e.preventDefault();
},