In Python, you might do something like
fout = open('out','w')
fin = open('in')
for line in fin:
fout.write(process(line)+"\n")
fin.close()
fout.close()
(I think it would be similar in many other languages as well). In Emacs Lisp, would you do something like
(find-file 'out')
(setq fout (current-buffer)
(find-file 'in')
(setq fin (current-buffer)
(while moreLines
(setq begin (point))
(move-end-of-line 1)
(setq line (buffer-substring-no-properties begin (point))
;; maybe
(print (process line) fout)
;; or
(save-excursion
(set-buffer fout)
(insert (process line)))
(setq moreLines (= 0 (forward-line 1))))
(kill-buffer fin)
(kill-buffer fout)
which I got inspiration (and code) from Emacs Lisp: Process a File line-by-line. Or should I try something entirely different? And how to remove the ""
from the print statement?
If you actually want batch processing of stdin
and sending the result to stdout
, you can use the --script command line option to Emacs, which will enable you to write code that reads from stdin
and writes to stdout
and stderr
.
Here is an example program which is like cat
, except that it reverses each line:
#!/usr/local/bin/emacs --script
;;-*- mode: emacs-lisp;-*-
(defun process (string)
"just reverse the string"
(concat (nreverse (string-to-list string))))
(condition-case nil
(let (line)
;; commented out b/c not relevant for `cat`, but potentially useful
;; (princ "argv is ")
;; (princ argv)
;; (princ "\n")
;; (princ "command-line-args is" )
;; (princ command-line-args)
;; (princ "\n")
(while (setq line (read-from-minibuffer ""))
(princ (process line))
(princ "\n")))
(error nil))
Now, if you had a file named stuff.txt
which contained
abcd
1234
xyz
And you invoked the shell script written above like so (assuming it is named rcat
):
rcat < stuff.txt
you will see the following printed to stdout:
dcba
4321
zyx
So, contrary to popular belief, you can actually do batch file processing on stdin
and not actually have to read the entire file in at once.