strcpy vs. memcpy

Question

What is the difference between memcpy() and strcpy()? I tried to find it with the help of a program but both are giving the same output.

int main()
{
    char s[5] = { 's', 'a', '\0', 'c', 'h' };
    char p[5];
    char t[5];
    strcpy(p, s);
    memcpy(t, s, 5);
    printf("sachin p is [%s], t is [%s]", p, t);
    return 0;
}

Output

sachin p is [sa], t is [sa]

Answer 1

what could be done to see this effect

Compile and run this code:

void dump5(char *str);

int main()
{
    char s[5]={'s','a','\0','c','h'};

    char membuff[5]; 
    char strbuff[5];
    memset(membuff, 0, 5); // init both buffers to nulls
    memset(strbuff, 0, 5);

    strcpy(strbuff,s);
    memcpy(membuff,s,5);

    dump5(membuff); // show what happened
    dump5(strbuff);

    return 0;
}

void dump5(char *str)
{
    char *p = str;
    for (int n = 0; n < 5; ++n)
    {
        printf("%2.2x ", *p);
        ++p;
    }

    printf("\t");

    p = str;
    for (int n = 0; n < 5; ++n)
    {
        printf("%c", *p ? *p : ' ');
        ++p;
    }

    printf("\n", str);
}

It will produce this output:

73 61 00 63 68  sa ch
73 61 00 00 00  sa

You can see that the "ch" was copied by memcpy(), but not strcpy().