I am new to Python. I am trying to adjust the format of a list which looks like below:
data=[1,10,313,4000,51234,123456]
and I would like to convert them to a list of strings with leading zeros:
result=['000001','000010','000313','004000','051234','123456']
each of the element has 6 digits.
I know for a single number X, I can do:
str(X).zfill(6)
but I am not sure how to apply this to a list. I would like to solve this problem without using a for loop.
Anyone could help? Thanks.
Apply the same zfill function in a list comprehension, like this
>>> [str(item).zfill(6) for item in data]
['000001', '000010', '000313', '004000', '051234', '123456']
Alternatively, you can use the string's format method, with format specifiers, like this
>>> ["{:06d}".format(item) for item in data]
['000001', '000010', '000313', '004000', '051234', '123456']
If you are going to do the formatting more often, then you can store that in a variable, like this
>>> formatter = "{:06d}".format
>>> [formatter(item) for item in data]
['000001', '000010', '000313', '004000', '051234', '123456']
If you are using Python 2.x, then you can use map and the formatter function, like this
>>> map(formatter, data)
['000001', '000010', '000313', '004000', '051234', '123456']
If you are using Python 3.x, map returns an iterable map object. So, you need to explicitly create a list, like this
>>> list(map(formatter, data))
['000001', '000010', '000313', '004000', '051234', '123456']