I have a dict which contains values like
DefaultListOrderedDict([('29.970', [1, 0, 0, 0, 0]), ('100.000', [0, 1, 0, 0, 1]), ('200.000', [0, 0, 1, 0, 0]), ('60.000', [0, 0, 0, 1, 0]), ('0.750', [0, 0, 1, 0, 0]), ('25.000', [0, 0, 0, 0, 1]), ('48.000', [0, 0, 1, 0, 0])])
I would like to sort it with values
I tried for k,v in sorted(Dict.items(),reverse = True):
But the sorting occurs in this order :
['0.750', '100.000', '200.000', '25.000', '29.970', '48.000', '60.000']
I don't understand the reason behind it. I would like to know the way how to sort it as :
['0.750', '25.000', '29.970', '48.000', '60.000', '100.000', '200.000']
You should convert keys to float:
OrderedDict(sorted(your_dict.items(), key=lambda item: float(item[0])))