I want to subtract y from x, which means remove one "A", three "B" and one "E" from x, so xNew
will be c("A", "C", "A","B","D")
. It also means
length(xNew)=length(x) - length(y)
x <- c("A","A","C","A","B","B","B","B","D","E")
y <- c("A","B","B","B","E")
setdiff doesn't work because
xNew <- setdiff(x,y)
xNew
[1] "C" "D"
match also doesn't work
xNew <- x[-match(y,x)]
xNew
[1] "A" "C" "A" "B" "B" "B" "D"
It removes "B" on the fifth position 3 times, so there are still three "B" left.
Is anyone know how to do this, is there a function available in R or we should write a private function? Thanks a lot in advance.
You can use the function pmatch
:
x[-pmatch(y,x)]
#[1] "A" "C" "A" "B" "D"
Edit
If your data can be strings of more than 1 character, here is an option to get what you want:
xNew <- unlist(sapply(x[!duplicated(x)],
function(item, tab1, tab2) {
rep(item,
tab1[item] - ifelse(item %in% names(tab2), tab2[item], 0))
}, tab1=table(x), tab2=table(y)))
Example
x <- c("AB","BA","C","CA","B","B","B","B","D","E")
y <- c("A","B","B","B","E")
xNew
# AB BA C CA B D
#"AB" "BA" "C" "CA" "B" "D"