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sqlmysqlselectgroup-bysql-order-by

MYSQL Select statment Order By with Group By

I have the following simple SQL statment

SELECT id, name, value_name, value_id
FROM table
GROUP BY id
ORDER BY value_id DESC

when grouping I would like to get the value_name and value_id of the tuple where the value_id is the biggest. The way it is i am getting the smallest value. For example

1, name1, valuename, 3     (where i know that there is a value_id of 5)

Can you please help?

Solution

  • change , value_id to , MAX(value_id) AS value_id in the field list...

    Actually, now that I look at it, I think what you want is something like this:

    SELECT a.id, a.name, MAX(b.value_id) AS value_id, (SELECT b.value_name FROM table AS b WHERE b.id = a.id AND b.value_id = MAX(a.value_id)) AS value_name
FROM table AS a 
GROUP BY a.id, a.name
ORDER BY value_id DESC

    The problem is that the table isn't fully normalized. So you have multiple rows with id and name being the same, but each has a unique value_id and value_name. So the only ways to get the value_name associated with the value_id is either through a subquery (what I did there), or a join...