I have been studying Python for a couple of weeks now, and just after easter, will be having a controlled assesment that will count towards my GCSE grade, for which I will be also marked for the criteria of something like the lentgh of my code.
The question was: Write a Python program that asks the user for a word, then calculates the prints the vowel value of the word entered.
What I want to know:
Is there anyway of shortening down this code?
And also:
How can the program be executed without printing out the "word" variable?
Above I have been given a rubric that I used in the code (in the control flow part).
score = 0
word = str(input("Input a word: "))
c = 0
for letter in word:
print(word[c])
c = c + 1
if letter == "a":
score = score + 5
if letter == "e":
score = score + 4
if letter == "i":
score = score + 3
if letter == "o":
score = score + 2
if letter == "u":
score = score + 1
print("\nThe score for your word is: " + score)
You can use sum and a dict, storing vowels as keys and the associated value as the values:
word = input("Input a word: ")
values = {"a":5,"e":4,"i":3,"o":2,"u":1}
print(sum(values.get(ch,0) for ch in word))
values.get(ch,0) will return 0 as a default value if the ch which is each char in the word is not a vowel therefore not in our dict.
sum(values.get(ch,0) for ch in word) is a generator expression where the variables are evaluated lazily when the next() method is called for generator object
In relation to your own code you should use if/elif's. A character can only have one value, if's are always evaluated but elif's are only evaluated if the previous statement evaluates to False:
score = 0
# already a str in python3 use raw_input in python2
word = input("Input a word: ")
for letter in word:
if letter == "a":
score += 5 # augmented assignment same as score = score + 5
elif letter == "e":
score += 4
elif letter == "i":
score += 3
elif letter == "o":
score += 2
elif letter == "u":
score += 1