Java: is there an int method like charAt()?

Question

I don't want "charAt(1);" to return the character at position 1 in the string... I want it to report all instances of "matching = 1;"

Take for example

int matching = 1;
int notMatching = 0;
int HI = matching;
int IH = notMatching; 
int searchString = theString.charAt(notMatching);

  int count = 0;
  int index = 0;

      while (0 < theString.length())
      {
      int  = theString.charAt(matching);
        if (theString.charAt(notMatching) == searchString)    
        {
        count = count + 1;
        }
        index = index + 1;
      }

Not a great example but basically what I want, or what this program is supposed to do is take a user input:

HIHIIH

and report the instances of HI spelled as IH... so the return would be for instance;

System.out.println("HI was spelled as IH" + count + "times");

EDIT: The "Duplicate" doesn't help me

Answer 1

You could use StringBuffer's reverse method and Pattern and Matcher as follows :

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class SearchReverseString {
    public static void main(String []args) {
        String str = "HIHIIH";
        String strToSearch = "HI";
        String strToSearchReversed = new StringBuffer(strToSearch).reverse().toString();
        Pattern strPattern = Pattern.compile(Pattern.quote(strToSearchReversed));
        Matcher matcher = strPattern.matcher(str);
        int counter = 0;
        while(matcher.find()) {
            ++counter;
        }
        System.out.println(strToSearch+" was spelt as "+strToSearchReversed+" "+counter+" times");
    }
}

The output is :

HI was spelt as IH 2 times

Note that in my program, str represents the input String and strToSearch represents the String to be searched in reverse order. The use of Pattern.quote ensures that any meta-characters are automatically escaped.