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c++operator-precedence

Can anyone explain why the x is displaying value 1 instead 2

I'm trying to brush-up my programming skills. Below program's output is 'I'm in else if 1'. I would like to know the reason behind, why the x value is not initialized to 2 instead it is showing 1. 

#include <iostream>
using namespace std;

int main()
{
   if (false)
   {
      cout << "I'm in if " << endl;
   }
   else if (int x=2 && true)
   {
      cout << "I'm in else if " << x << endl;
   }
   else
   {
      int y = x;
      cout << y << endl;
   }

   return 0;
}
Solution

  • According to operator precedence,

    if (int x=2 && true)

    is parsed as

    if (int x = (2 && true))

    so x = true so 1.