MySql prepared statement is not working for SELECT,but works for all other statement

Question

I have found same question at SO

Prepared statement works for INSERT but not for SELECT

and tried to follow it,but no luck.One more thing, that question is on OOP structure,but my one is procedural style

Here is my code

$stmt = mysqli_stmt_init($connect_dude);

if(mysqli_stmt_prepare($stmt,"SELECT headx FROM main_page WHERE user_id=?")){

  mysqli_stmt_bind_param($stmt, "i", $idx);
  mysqli_stmt_execute($stmt);
  mysqli_stmt_bind_result($stmt, $head);
  printf("Number of rows: %d.\n", mysqli_stmt_num_rows($stmt));

  ...................
  ...................
}

It shows Number of rows:0 where it should be 1.That's why,I cannot proceed further to fetch data from database.I tried my best to fix the problem,but couldn't make it.

Your help would be really appreciated.

Thanks for your time.

Answer 1

I have figured it out.

Need to use mysqli_stmt_store_result($stmt)

mysqli_stmt_bind_param($stmt, "i", $idx);
mysqli_stmt_execute($stmt);
mysqli_stmt_store_result($stmt);
printf("Number of rows: %d.\n", mysqli_stmt_num_rows($stmt));

gives me Number of rows:1

As of php.net

You must call mysqli_stmt_store_result() for every query that successfully produces a result set (SELECT, SHOW, DESCRIBE, EXPLAIN)

BUT

NOT MUST for UPDATE,DELETE AND INSERT.

Thanks everyone.