Ruby multiple OR conditions

Question

In ruby, is there a more concise way of expressing multiple OR conditions in an if statement?

For example this is the code I have:

if call_type == "GPRS" || call_type == "SMS" || call_type == "MMS" || call_type == "USSD" || call_type == "TELEPHONY"
  #do something
end

There will be more OR conditions and I don't want to write like this multiple times. Is there a better way to express this in ruby 2.1.0 ?

Thanks in advance.

Answer 1

You could use Array#include?:

if %w(GPRS SMS MMS USSD TELEPHONY).include? call_type
  # ...
end

Or a case expression:

case call_type
when 'GPRS', 'SMS', 'MMS', 'USSD', 'TELEPHONY'
  # ...
end

Or a regular expression:

if call_type =~ /^(GPRS|SMS|MMS|USSD|TELEPHONY)$/
  # ...
end

As noted by cremno, ^ and $ match beginning and end of line. You can use \A and \z instead if call_type contains multiple lines.