Extending mysqli and using multiple classes

Question

I'm new to PHP oop stuff.

I'm trying to create class database and call other classes from it. Am I doing it the right way?

class database:

class database extends mysqli {

private $classes = array();

public function __construct() {
parent::__construct('localhost', 'root', 'password', 'database');
    if (mysqli_connect_error()) {
    $this->error(mysqli_connect_errno(), mysqli_connect_error());
    }
}

public function __call($class, $args) {
    if (!isset($this->classes[$class])) {
    $class = 'db_'.$class;
    $this->classes[$class] = new $class(); 
    }
return $this->classes[$class];
}

private function error($eNo, $eMsg) {
die ('MySQL error: ('.$eNo.': '.$eMsg);
}

}

class db_users:

class db_users extends database {

public function test() {
echo 'foo';
}

}

and how I'm using it

$db = new database();
$db->users()->test();

Is it the right way or should it be done another way?

Thank you.

Answer 1

You can do it that way, there's nothing wrong with that (I do something similar quite often). The only thing I would suggest is using exceptions instead of die (that way you can safely handle the error)...

protected function error($eNo, $eMsg, $extra = '') {
    throw new Exception('MySQL error: ['.$eNo.'] '.$eMsg.': '.$extra);
}

Plus, I'd suggest overloading the query method as well

public function query($sql, $result_mode = MYSQLI_STORE_RESULT) {
    $result = parent::query($sql, $result_mode);
    if ($result === false) {
         $this->error($this->errno, $this->errstr, $sql);
    }
    return $result;
}

I'd also suggest storing a copy of the $db object inside of the child class. So:

class db_users extends database {
    protected $db = null;

    public function __construct(Database $db) {
        $this->db = $db;
    }

    public function test() {
        echo 'foo';
    }
}

Then, in __call:

if (!isset($this->classes[$class])) {
    $class = 'db_'.$class;
    $this->classes[$class] = new $class($this); 
}