I am trying to order all of the scores in order of each user's score from highest to lowest. I have attempted this with the code below:
import collections
from collections import defaultdict
from operator import itemgetter
worker_scores = collections.defaultdict(lambda: collections.deque(maxlen=3))
import operator
worker_scores.clear()
with open('score_names.txt') as f:
for line in f:
worker,score = line.split(":")
worker_scores[worker].append(int(score))
print("\nThis prints all the highest scores.\n")
for worker in sorted(worker_scores, key=itemgetter(1,2,3), reverse=True):
print(worker," ".join(map(str,worker_scores[worker])))
# This should print the maximum value for each key
print max(worker_scores, key=worker_scores.get)
My text file also appears as follows:
AdamJohnson:10
AdamJohnson:20
AdamJohnson:30
AdamJohnson:40
AdamJohnson:60
AdamJohnson:50
MichaelJordan:70
MichaelJordan:80
MichaelJordan:100
MichaelJordan:90
DavidSnowman:15
DavidSnowman:20
DavidSnowman:30
DavidSnowman:25
The outcome of the IDLE is as follows:
This prints all the highest scores.
MichaelJordan 80 100 90
AdamJohnson 40 60 50
DavidSnowman 20 30 25
This is what I desired, where the highest scores are at the top and the lowest scores are at the bottom. I discovered the itemgetter technique to do this so I have now accomplished part of my solution.
For the second part, I want the maximum key for each value to be printed. I can use the sorted key to print the keys in alphabetical order, but I cannot print the maximum value for each key. I have used this line from above:
print max(worker_scores, key=worker_scores.get)
To get this result:
AdamJohnson:60
MichaelJordan:100
DavidSnowman:30
But this error arrives: Invalid Syntax (Max).
What is going wrong?
You don't need to use max, you can use sorted function and collections.OrderedDict :
d=OrderedDict()
for k,v in sorted(((i,j.pop()) for i,j in worker_scores.items()),key=operator.itemgetter(1),reverse=True):
d[k]=v
print d
OrderedDict([('MichaelJordan', 100), ('DavidSnowman', 30), ('AdamJohnson', 60)])
All that i have done in preceding code is loop over the worker_scores items and pop the last (max) element in deque,(j.pop()) but note that you need to use reverse=True to have the desire order, then add them to OrderedDict.
And for print the items :
for k,v in d.items():
print ':'.join((k,str(v)))
MichaelJordan:100
DavidSnowman:30
AdamJohnson:60