Shape with selector as color doesn't works

Question

I want to create a shape with selector as solid color.

On Android 5.0+, this code works perfectly, but on 4.X, it doesn't works.

shape.xml :

<?xml version="1.0" encoding="utf-8"?>
<shape android:shape="rectangle" xmlns:android="http://schemas.android.com/apk/res/android">
    <solid android:color="@color/my_selector"/>

    <size android:height="40dp" android:width="40dp"/>

    <corners android:radius="10dp" />
</shape>

my_selector.xml

<?xml version="1.0" encoding="UTF-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">

    <item
        android:color="@color/color_1"
        android:state_checked="false"/>

    <item
        android:color="@color/color_2"
        android:state_checked="true"/>
</selector>

This drawable is applied to CheckBox background.

Answer 1

you should change order to write state like this and use your shape in item:

<?xml version="1.0" encoding="UTF-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">

   <item android:state_checked="true">
       <shape android:shape="rectangle" >
          <solid android:color="@color/my_selector"/>

         <size android:height="40dp" android:width="40dp"/>

         <corners android:radius="10dp" />
      </shape>
   </item>
   <item>
      <shape android:shape="rectangle" >
          <solid android:color="@color/my_deselec"/>

         <size android:height="40dp" android:width="40dp"/>

         <corners android:radius="10dp" />
      </shape>
   </item>

</selector>