How to change column position in powershell?

Question

Is there any easy way how to change column position? I'm looking for a way how to move column 1 from the beginning to the and of each row and also I would like to add zero column as a second last column. Please see txt file example below.
Thank you for any suggestions.

File sample

TEXT1,02/10/2015,55.930,57.005,55.600,56.890,1890  
TEXT2,02/10/2015,51.060,52.620,50.850,52.510,4935
TEXT3,02/10/2015,50.014,50.74,55.55,52.55,5551

Output:

02/10/2015,55.930,57.005,55.600,56.890,1890,0,TEXT1  
02/10/2015,51.060,52.620,50.850,52.510,4935,0,TEXT2
02/10/2015,50.014,50.74,55.55,52.55,5551,0,TEXT3

Answer 1

Another option:

#Prepare test file
(@'
TEXT1,02/10/2015,55.930,57.005,55.600,56.890,1890  
TEXT2,02/10/2015,51.060,52.620,50.850,52.510,4935
TEXT3,02/10/2015,50.014,50.74,55.55,52.55,5551
'@).split("`n") |
foreach {$_.trim()} | 
sc testfile.txt

#Script starts here
$file = 'testfile.txt'

(get-content $file -ReadCount 0) |
foreach  {
'{1},{2},{3},{4},{5},{6},0,{0}' -f $_.split(',')
} | Set-Content $file

#End of script

#show results    
get-content $file

02/10/2015,55.930,57.005,55.600,56.890,1890,0,TEXT1
02/10/2015,51.060,52.620,50.850,52.510,4935,0,TEXT2
02/10/2015,50.014,50.74,55.55,52.55,5551,0,TEXT3