originally the lists was nested within another list. each element in the list was a series of strings.
['aaa664847', 'Completed', 'location', 'mode', '2014-xx-ddT20:00:00.000']
I joined the strings within the list and then append to results.
results.append[orginal]
print results
['aaa664847, Completed, location, mode, 2014-xx-ddT20:00:00.000']
['aaa665487, Completed, location, mode, 2014-xx-ddT19:00:00.000']
['aaa661965, Completed, location, mode, 2014-xx-ddT18:00:00.000']
['aaa669696, Completed, location, mode, 2014-xx-ddT17:00:00.000']
['aaa665376, Completed, location, mode, 2014-xx-ddT16:00:00.000']
I am looking to write each list to a text file. The number of lists can vary.
My current code:
fullpath = ('O:/Location/complete.txt')
outfile = open(fullpath, 'w')
outfile.writelines(results)
returns only the first list in the text file:
aaa664847, Completed, location, mode, 2014-xx-ddT20:00:00.000
I would like the text file to include all results
Assuming results is a list of lists:
from itertools import chain
outfile = open(fullpath, 'w')
outfile.writelines(chain(*results))
itertools.chain will concat the lists into a single list.
But writelines will not write newlines. For that you can do this:
outfile.write("\n".join(chain(*results))
Or, plainly (assuming all list inside results have only one string):
outfile.write("\n".join(i[0] for i in results)