I have column (Numbers) which has values as follows:
1,2,3
1,2,3,
1,2,3,,,
1,2,3,,,,,,
I want to Trim all the Commas at the end of string, So that result would be
1,2,3
1,2,3
1,2,3
1,2,3
I have tried below Query but by this we can remove only one last comma
DECLARE @String as VARCHAR(50)
SET @String='1,2,3,4,,,,,,,,,,,,,,,,'
SELECT CASE WHEN right(rtrim(@String),1) = ',' then substring(rtrim(@String),1,len(rtrim(@String))-1)
ELSE @String
END AS TruncString
How can I remove all the commas at the end of string?
You can do this using:
LEFT(Numbers, LEN(Numbers) - (PATINDEX('%[^,]%', REVERSE(Numbers)) - 1))
The premise of this is you first reverse the string using REVERSE
:
REVERSE(Numbers) --> ,,,,,,3,2,1
You then find the position of the first character that is not a comma using PATINDEX
and the pattern match [^,]
:
PATINDEX('%[^,]%', REVERSE(Numbers)) --> ,,,,,,3,2,1 = 7
Then you can use the length of the string using LEN
, to get the inverse position, i.e. if the position of the first character that is not a comma is 7 in the reversed string, and the length of the string is 10, then you need the first 4 characters of the string. You then use SUBSTRING
to extract the relevant part
A full example would be
SELECT Numbers,
Reversed = REVERSE(Numbers),
Position = PATINDEX('%[^,]%', REVERSE(Numbers)),
TrimEnd = LEFT(Numbers, LEN(Numbers) - (PATINDEX('%[^,]%', REVERSE(Numbers)) - 1))
FROM (VALUES
('1,2,3'),
('1,2,3,'),
('1,2,3,,,'),
('1,2,3,,,,,,'),
('1,2,3,,,5,,,'),
(',,1,2,3,,,5,,')
) t (Numbers);
EDIT
In response to an edit, that had some errors in the syntax, the below has functions to trim the start, and trim both sides of commas:
SELECT Numbers,
Reversed = REVERSE(Numbers),
Position = PATINDEX('%[^,]%', REVERSE(Numbers)),
TrimEnd = LEFT(Numbers, LEN(Numbers) - (PATINDEX('%[^,]%', REVERSE(Numbers)) - 1)),
TrimStart = SUBSTRING(Numbers, PATINDEX('%[^,]%', Numbers), LEN(Numbers)),
TrimBothSide = SUBSTRING(Numbers,
PATINDEX('%[^,]%', Numbers),
LEN(Numbers) -
(PATINDEX('%[^,]%', REVERSE(Numbers)) - 1) -
(PATINDEX('%[^,]%', Numbers) - 1)
)
FROM (VALUES
('1,2,3'),
('1,2,3,'),
('1,2,3,,,'),
('1,2,3,,,,,,'),
('1,2,3,,,5,,,'),
(',,1,2,3,,,5,,')
) t (Numbers);