I am trying to write a small script that will take url as input and will parse it.
Following is my script
#! /usr/bin/env python
import sys
from urlparse import urlsplit
url = sys.argv[1]
parseUrl = urlsplit(url)
print 'scheme :', parseUrl.scheme
print 'netloc :', parseUrl.netloc
But when I execute this script with ./myscript http://www.example.com
it shows following error.
AttributeError: 'tuple' object has no attribute 'scheme'
I am new to python/scripting, where am I doing wrong?
Edit: Python version that I am using is Python 2.7.5
You don't want scheme. Instead in this case you want to access the 0 index of the tuple and the 1 index of the tuple.
print 'scheme :', parseUrl[0]
print 'netloc :', parseUrl[1]
urlparse uses the .scheme and .netloc notation, urlsplit instead uses a tuple (refer to the appropriate index number):
This is similar to urlparse(), but does not split the params from the URL. This should generally be used instead of urlparse() if the more recent URL syntax allowing parameters to be applied to each segment of the path portion of the URL (see RFC 2396) is wanted. A separate function is needed to separate the path segments and parameters. This function returns a 5-tuple: (addressing scheme, network location, path, query, fragment identifier).
The return value is actually an instance of a subclass of tuple. This class has the following additional read-only convenience attributes:
Attribute Index Value Value if not present scheme 0 URL scheme specifier empty string netloc 1 Network location part empty string path 2 Hierarchical path empty string query 3 Query component empty string fragment 4 Fragment identifier empty string username User name None password Password None hostname Host name (lower case) None port Port number as integer, if present None