So my task is to see and check a positive integer if its a palindrome. I've done everything correctly but need help on the final piece. And that the task of generating a new a palindrome from the one given given by the user. Am i on the right track with the while loop or should i use something else? So the result is if you put 192 it would give back Generating a palindrome.... 483 867 1635 6996
"""Checks if the given, positive number, is in fact a palindrome"""
def palindrome(N):
x = list(str(N))
if (x[:] == x[::-1]):
return True
else: return False
"""Reverses the given positive integer"""
def reverse_int(N):
r = str(N)
x = r[::-1]
return int(x)
def palindrome_generator():
recieve = int(input("Enter a positive integer. "))
if (palindrome(recieve) == True):
print(recieve, " is a palindrome!")
else:
print("Generating a palindrome...")
while palindrome(recieve) == False:
reverse_int(recieve) + recieve
If I understand your task correctly, the following should do the trick:
def reverse(num):
return num[::-1]
def is_pal(num):
return num == reverse(num)
inp = input("Enter a positive number:")
if is_pal(inp):
print("{} is a palindrome".format(inp))
else:
print("Generating...")
while not is_pal(inp):
inp = str(int(inp) + int(reverse(inp)))
print(inp)
The variable inp is always a string and only converted to int for the arithmetic.