How to parse command line arguments with SWITCH in BATCH file

Question

We are trying to make a switch statement which is parsing command line argument in a batch file.

mybatch.bat -a 10 -b name -c India --zipcode 20

Only -a, -b, -c are parsing parameter (which is starts with -).

Our code will be like:

for %%x in (%*) do (
     switch(%%x) (
          case a:
                 SET first_number=%arg%
                 break
          case b:
                 SET name=%arg%
          case c:
                 for %%x in (%*) do (
                       SET place =%place% %arg%
                  )
          default:
                  echo wrong parameter
           )

Answer 1

Normally you try to keep things simple and have a set order for the parameters. To handle parameters in any, random order is a lot more effort than just knowing that %1 = number, %2 = name and %3 onwards = place.

That said, here's an attempt at a solution. I'm ignoring --params in the place section, just joining the values together.

@echo off
setlocal

:loop
if x%1 equ x goto done
set param=%1
if %param:~0,1% equ - goto checkParam
:paramError
echo Parameter error: %1 

:next
shift /1
goto loop

:checkParam
if "%1" equ "-a" goto A
if "%1" equ "-b" goto B
if "%1" equ "-c" goto C
goto paramError

:A
    shift /1
    set first_number=%1
    goto next

:B
    shift /1
    set name=%1
    goto next

:C
    set place=
:GetPlaces
    shift /1
    set param=%1
    if not defined param goto donePlaces
    if %param:~0,2% equ -- (
        shift /1
        goto processPlace
    )
    if %param:~0,1% equ - goto donePlaces
:processPlace
echo.%place%
    if x%1 neq x (
        set place=%place% %1
        goto GetPlaces
    )
:donePlaces
    rem remove leading space
    if defined place set place=%place:~1%
    goto loop



:done

echo num=%first_number%     name=%name%     place=%place%